Question

if secθ=5/4 then cscθ=​

Answer 1

$sec \: θ = \frac{5}{4} = \frac{hyp}{adj}$

$hy {p}^{2} = ad {j}^{2} + {opp}^{2} \\ {5}^{2} = {4}^{2} + {opp}^{2} \\ 25 = 16 + {opp}^{2} \\ 25 - 16 = op {p}^{2} \\ op {p}^{2} = 9 \\ opp = \sqrt{9} \\ opp = 3$

$cosec \: θ = \frac{hyp}{opp} = \frac{5}{3}$