If sec 5A = cosec(A-36) and 5A is an acute angle, show that A = 21
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sec5A=cosec(A-36)
cosec (90-5A)=cosec(A-36)
90-5A=A-36
90+36=A+5A
126=6A
A=126/6
A=21
hence proved is A= 21
cosec (90-5A)=cosec(A-36)
90-5A=A-36
90+36=A+5A
126=6A
A=126/6
A=21
hence proved is A= 21
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