if secθ=5x. tanθ = 5/X THEN find 5(x2 -1/x2)=?
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Given: 5x = sec θ, and 5/x = tan θ
Consider 5(x2 – (1/ x2))
= (1/5) [sec2 θ – tan2 θ]
= (1/5)[1]
= 1/5 (∵ sec2 x – tan2 x = 1)
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