Question

if sec 6A=cosec(A+6),where 6A is an actual angle,find the value of A

Answer 1

sec6A = cosec( A + 6 )



we know, sec A = cosec( 90 - A )


cosec( 90 - 6A ) = cosec( A + 6 )


90 - 6A = A + 6

90 - 6 = A + 6A

84 = 7A

84 / 7 = A

12 = A



$\:$
Therefore value of A is 12.

Answer 2

sec 6A=cosec(A+6)

==> cosec(90-A) = cosec (A+6)

==> 90-A = A+6

==>  90-6 = A+A

==> 84 = 2A

==> A = 84/2

==> A = 42