Question

If sec 6a =cosec(A+6), where6A is an actual angle, find the value of A

Answer 1

sec 6a = cosec(a+6)
cosec (90-6a)= cosec(a+6)
90-6a=a+6
90+6=a+6a
96=7a
96/7=a

Answer 2

we know if sec a=cosec b then a+b=90

soo

6a+A+6=90
6a+A=84
A=84-6a

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