Question

If sec A = 13/12, find sinA and cotA.​

Answer 1

Step-by-step explanation:

secA = 13/12

=>hypotenuse=13

=>base=12

using Pythagoras theorem,

(hypotenuse)²=(base)²+(perpendicular)²

=> (13)²=(12)²+(perpendicular)²

=> 169 - 144 = (perpendicular)²

=> √25 = perpendicular....

= 5

we know that,

sinA = perpendicular/hypotenuse

sinA = 5/13

also,

cosA = 1/secA

=> cosA = 12/13

hope this helps....... Mark as brainliest...

Answer 2

SecA=13/12
CosA=12/13
SinA =5/13 as sin^2A+cos^2A=1
TanA=5/12 as tanA=sinA/CosA