Question

If sec A = 13/5. Find 2sin theta + 3 cos theta / 4sin theta - 9 cos theta

Answer 1

Answer:

13

Step-by-step explanation:

secA=13/5=H/B

By pythagoras theorem

H^2=P^2+B^2

P^2=13^2-5^2

=169-25

=144

P=√144=12

sinA=P/H=12/13

cosA=B/H=5/13

(2sinA+3cosA)/(4sinA-9cosA)

=[2(12/13)+3(5/13)]/[4(12/13)-9(5/13)]

=(24/13+15/13)/(48/13-45/13)

=(39/13)/(3/13)

=39/3

=13