Question

If sec A = 15 / 7 ( 15 upon 7 ) and A + B = 90 then the value of cosec B =

15 / 7
15 / 8
7 / 15
8 / 15​

Answer 1

Answer:

15/7

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Answer 2

$\huge{ \boxed{ \mathfrak \red{answer}}}$

secA = cosecB = \frac{15}{7}715

$\huge{ \boxed{ \mathfrak{ \blue{explation}}}}$

Given

A+B = 90°

=> A = 90°-B---(1)

and

secA=\frac{15}{7}secA=715

\implies sec(90-B)=\frac{15}{7}⟹sec(90−B)=715

/* From (1) */

\implies cosecB=\frac{15}{7}⟹cosecB=715

/* We know that,

sec(90-B) = cosecB */

Therefore,

secA = cosecB = \frac{15}{7}715