If sec A=15÷7 andA+B=90,find the value of cosec B?
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Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15
Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 A + B = 90 or A = 90 - B
Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 A + B = 90 or A = 90 - B CosA = Cos(90-B)
Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 A + B = 90 or A = 90 - B CosA = Cos(90-B) 7/15 = SinB
Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 A + B = 90 or A = 90 - B CosA = Cos(90-B) 7/15 = SinB CosecB = 1/SinB = 1/ 7/15 = 15/7
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