Question

If sec A=17/15 then find the value of 2 sin A + tan A /2tan A - sin A​

Answer 1

Given :  sec A=17/15

To Find :  (2 SinA + tanA)(2tanA  - sinA)

Solution:

(2 SinA + tanA)(2tanA  - sinA)

sinA = cosA.tanA

=  (2 cosAtan + tanA)(2tanA  - cosAtanA)

= tanA(2cosA + 1) / tanA(2 - cosA)

= (2cosA + 1) / (2 - cosA)

sec A=17/15 => cosA  = 15/17  

= (2(15/17) + 1) / ( 2 - 15/17)

= 47 / 19

(2 SinA + tanA)(2tanA  - sinA)  = 47/19

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