If sec A=17/15 then find the value of 2 sin A + tan A /2tan A - sin A
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Answer:
secA=17/15
cosA= 15/17
create triangle
sinA= 8/17
sinA/cosA=tan A
tanA=8/15
Now ,
2*8/15+1/2-8/17. ( here tanA/2tanA=1/2)
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Answered by
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Given : sec A=17/15
To Find : (2 SinA + tanA)(2tanA - sinA)
Solution:
(2 SinA + tanA)(2tanA - sinA)
sinA = cosA.tanA
= (2 cosAtan + tanA)(2tanA - cosAtanA)
= tanA(2cosA + 1) / tanA(2 - cosA)
= (2cosA + 1) / (2 - cosA)
sec A=17/15 => cosA = 15/17
= (2(15/17) + 1) / ( 2 - 15/17)
= 47 / 19
(2 SinA + tanA)(2tanA - sinA) = 47/19
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