if (sec A-2)(tan3A-1) = 0 find a
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Answered by
7
Answer:
Step-by-step explanation:
Solve the equation (sec A-2)(tan 3A-1)=0
(sec A-2) = 0
=> secA - 2 = 0
=> secA = 2
=> 1/CosA = 2
=> 2CosA = 1
=> CosA = 1/2
=> A = 60°
tan 3A-1 = 0
=> tan3A = 1
=> 3A = 45° or 225°
=> A = 45° /3 or 225°/3
=> A = 15° or 75°
A = 15° , 60° , 75° are the solution
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Answered by
3
According to the question .
Step by step explaination
Sec A - 2 = 0
(Sec A = 1/Cos A)
1/CosA = 2
2 CosA =1
Cos A =1/2
A = 60°
Tan 3 A=1.
3A=1/Tan
A = 45/3
A= 15°
A CAN BE 60° , 15° , 75°.
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