Math, asked by mohammedhajwani5, 1 year ago

if (sec A-2)(tan3A-1) = 0 find a​

Answers

Answered by Anonymous
7

Answer:

A = 15° , 60° , 75°  are \:  the  \: solution

Step-by-step explanation:

Solve the equation (sec A-2)(tan 3A-1)=0

(sec A-2) = 0

=> secA - 2 = 0

=> secA = 2

=> 1/CosA = 2

=> 2CosA = 1

=> CosA = 1/2

=> A = 60°

tan 3A-1 = 0

=> tan3A = 1

=> 3A = 45° or 225°

=> A = 45° /3 or 225°/3

=> A = 15° or 75°

A = 15° , 60° , 75° are the solution

hope it helped you friend if it helps you mark it as brainliest

Answered by aanshiprincess20
3

According to the question .

Step by step explaination

Sec A - 2 = 0

(Sec A = 1/Cos A)

1/CosA = 2

2 CosA =1

Cos A =1/2

A = 60°

Tan 3 A=1.

3A=1/Tan

A = 45/3

A= 15°

A CAN BE 60° , 15° , 75°.

THANK YOU

MARK ME AS BRAINLIEST

Similar questions