Math, asked by vikasgayakwad375, 2 months ago

If sec A=5/3 , then find the value of sin A x Cos A.​

Answers

Answered by chaursiapooja4
0

Answer:

12\25 and p= 4

Step-by-step explanation:

we have given sec A = h\b = 5\3

by phthagoreas therom

h^2= p^2+ s^2

(5)^ 2 = p^ 2+ (3)^ 2

25= p ^2+ 9

25-9= p^2

16= p^2

√16= p

4 = p

so ,we have find p= 4

then sin A = p\h =4\5

cos A = b\h = 3\5

sin A × cos A = 4\5 × 3 \5 = 12\25

therefore , answer is 12\25

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