If sec A=5/3 , then find the value of sin A x Cos A.
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Answer:
12\25 and p= 4
Step-by-step explanation:
we have given sec A = h\b = 5\3
by phthagoreas therom
h^2= p^2+ s^2
(5)^ 2 = p^ 2+ (3)^ 2
25= p ^2+ 9
25-9= p^2
16= p^2
√16= p
4 = p
so ,we have find p= 4
then sin A = p\h =4\5
cos A = b\h = 3\5
sin A × cos A = 4\5 × 3 \5 = 12\25
therefore , answer is 12\25
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