Question

If sec A =5/3,then find the value of tanA-sinA/1+tanA.sinA.​

Answer 1

Answer:

sinx = 4/5

tanx = 4/3

$= \frac{ \frac{4}{3} - \frac{4}{5} }{1 + \frac{4}{3} \times \frac{4}{5} } \\ \\ = \frac{ \frac{8}{15} }{1 + \frac{16}{15} } \\ \\ = \frac{8}{31}$