If 'sec A' , find 'sin A=(m^(2))/(n^(2))' .
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Step-by-step explanation:
the answer is in the attachment
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Answered by
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Answer:
sinA=
m
2
+n
2
2mn
sinA=
H
P
=
m
2
+n
2
2mn
Heren, P=2mn and H=m
2
+n
2
We know, H
2
=P
2
+B
2
(m
2
+n
2
)
2
=4m
2
n
2
+B
2
m
4
+n
4
+2m
2
n
2
=4m
2
n
2
+B
2
m
4
+n
4
−2m
2
n
2
=B
2
(m
2
−n
2
)
2
=B
2
B=m
2
−n
2
Thus, tanA=
B
P
=
m
2
−n
2
2mn
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