Question

if sec A is 17/8, verify that: (3 - 4Sin2A)/(4cos2A - 3) = (3 - tan2A)/(1 - 3tan2A)

Answer 1

Required changes will b
sin2A=2.sinA.cosA
sinA=1-cos^2A
cos^2A=1/sec^2A
cos2A=1+cos^2A
cos^2A=1/sec^2A

Answer 2

Here is the solution.