Math, asked by shambhavirai2532, 11 months ago

If sec a is equal to 17 by 8 then verify that 3 - 4 sin square a by 4 cos square a minus 3 is equal to 3 minus

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Answered by Anonymous

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Answer:

secA = 17/8, show that 3- 4sin^2A/4cos^2A-3 = 3tan^2A/1-3tan^2A. ... We know, sec A = Hypotenuse/Base = 17/8

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