Question

if sec a is equal to root 2 find 3 cos square A + 2 sin square A upon a tangent square A minus cos square A​

Answer 1

What did you mean by upon tangent square?  And which grade portions is this from?

Answer 2

Given,

secA = root 2

since sec 45' = root 2

therefore, A=45'

then the equation becomes:

3cot²45' + 2sin²45' / tan²45' - cos²45'

3(1)² + 2×(1/root 2)² / (1)² - (1/root2)²

3+1 / 1-1/2

4 / 1/2

4×2 = 8 ans.