Question

If sec A-tan A=1/3, find the value of sec A and tan A.

Answer 1

We know that:-
[secA^2-tanA^2=1]
(secA^2-tanA^2)=1
(secA+tanA)( secA-tanA)=1
(secA+tanA)*1/3=1     [secA-tanA=1/3]
(secA+tanA)/3=1
(secA+tanA)=3
(secA-tanA)=1/3
By simultenous equation we get:-
tanA=4/3
secA=5/3