If sec A+ tan A= 13/5 , then what is the value of sec A – tan A?
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answer is 5/13
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Answered by
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Step-by-step explanation:
We know that sec2A-tan2A=1,
(SecA+tanA)(secA-tanA)=1
13/5(secA-tanA)=1
SecA-tanA=5/13
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