If sec A- tan A = √2 tanA, then show that secA + tan A = √2 secA.
Answers
Answered by
0
Answer:
LHS=
secA+tanA
secA−tanA
=
secA+tanA
secA−tanA
×
secA−tanA
secA−tanA
=
sec
2
A−tan
2
A
sec
2
A−2secAtanA+tan
2
A
=1+tan
2
A−2secAtanA+tan
2
A
=1−2secAtanA+2tan
2
A
Similar questions