Math, asked by mayank2734, 2 months ago

If sec A- tan A = √2 tanA, then show that secA + tan A = √2 secA.

Answers

Answered by portugalindia567

0

Answer:

LHS=

secA+tanA

secA−tanA

=

secA+tanA

secA−tanA

×

secA−tanA

secA−tanA

=

sec

2

A−tan

2

A

sec

2

A−2secAtanA+tan

2

A

=1+tan

2

A−2secAtanA+tan

2

A

=1−2secAtanA+2tan

2

A

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