If sec A + tan A=2 then find the value of sin A + cos A?
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SecA +tanA=2
(SecA-tanA)^2=1
(SecA+tanA)(SecA-tanA)=1
SecA-tanA=1/2
SecA+tanA=2
SecA-tanA=1/2
_. +. -. (Subtraction)
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2tanA=2-1/2
2TanA=4-1/2
TanA=3/4. (opp/adj)
(Draw the figure you can understand and do Pythagoras therom)
(Hypotenuse =5)
SinA+cosA= 3/5+4/5=7/5
(SecA-tanA)^2=1
(SecA+tanA)(SecA-tanA)=1
SecA-tanA=1/2
SecA+tanA=2
SecA-tanA=1/2
_. +. -. (Subtraction)
---------------------
2tanA=2-1/2
2TanA=4-1/2
TanA=3/4. (opp/adj)
(Draw the figure you can understand and do Pythagoras therom)
(Hypotenuse =5)
SinA+cosA= 3/5+4/5=7/5
shrdxx5:
check there is something wrong in between
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