Question

if sec A+Tan A =3/2 then 5/12 =​

Answer 1

(secA+tanA)=3/2..............(1).

(secA+tanA)(secA-tanA)/(secA-tanA)=3/2

(sec²A-tan²A)/(secA-tanA)=3/2

1/(secA-tanA)=3/2

secA-tanA=2/3...........(2)

now substract eqn 1 - eqn 2

2tanA=3/2 -2/3=(9-4)/6=5/6

tanA=5/12.