Question

If sec A+tan A=3/2 then sec A is

Answer 1

sec A+tan A=3/2
Squaring both side
Sec^2 A + tan^2A +2tanA secA= 9/4
Sec^2 A + Sec^2 A -1 +2tanA secA= 9/4
2 sec^2A + +2tanA secA= 9/4 +1
2secA( secA + tanA) = 13/4
2secA x 3/2 = 13/4
3 secA,= 13/4
SecA= 13/12