Math, asked by adityasingh7470, 1 year ago

If Sec A+ tan A = 3
then sec A - tan A

Answers

Answered by Anonymous
1

Answer:

\green{secA-TanA=1/3}

Step-by-step explanation:

\boxed{given}

secA+tanA=3

\boxed{Tofind}

secA-TanA

\blue{Answer}

we know the identity

sec {}^{2}   - tan {}^{2}  = 1

using

\green{(a+b)(a-b)=a^2-b^2}

(sec + tan)(sec - tan) = 1

secA +TanA=3

putting this value we get

(3)(sec  - tan) = 1

\boxed{secA-tanA=1/3}

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