Question

If sec A + tan A= m and sec A- tan A, prove that mn= 1

Answer 1

Hi friend!!

Given,

sec A + tan A= m and sec A- tan A=n

Now,

m×n=(sec A + tan A)(sec A- tan A)

Using identity (a+b)(a-b)=a²-b²,we get

mn=sec²A- tan²A

We know that sec²x- tan²x=1

→mn=1

Hence proved.

I hope this will help you

:D

Answer 2

Sec A + tan A = m
Sec A -tan a = n
---------------------------
Sec^2 A - tan ^2 A = mn

But sec^2 A - tan^2 A = 1 ( formula)

Hence mn = 1

Therefore solved or proved or verified whatever...

Thank u★★★
#ckc