Question

If sec a + tan a =m then sec^4 a -tan^4a -2sec a tan a ?????!??????????????(??????(?

Answer 1

I think it is sec⁴a-tan⁴a +2secatana
then we get answer as m²

Answer 2

given,sec a +tan a =m

then, sec^4 a - tan^4 a - 2sec a tan a=???

Step-by-step explanation:

=(sec^2 a + tan^2 a)(sec^2 a - tan^2 a) - 2sec a tan a

=sec^2 a + tan^2 a - 2sec a tan a

=(sec a - tan a)^2

now,

We know that,

sec^2 a - tan^2 a = 1

=(sec a - tan a) (sec a + tan a)=1

=(sec a - tan a) (m) = 1

=(sec a - tan a)=1/m

on square both sides,

=(sec a - tan a)^2 = 1/m^2