If sec A + tan A = p and sec A - tan A = 1/p then what are the values of cos A and sin A
Answers
Answered by
1
Answer:
please mark me brain list
Step-by-step explanation:
sec@+ tan@ = p -(1) sec²@-tan²@=1 (sec@ + tan@)x(sec@ - tan@) = 1 px(sec@tan@) = 1 sec@tan@=1/p--(2)
(1) + (2)
2 sec@= = (p+1/p) = (p²+1)/p sec@= (p²+1)/2p cos@ = 2p/(p²+1)
(1)-(2)
2tan@p-1/p (p²-1)/p = tan@ = (p²-1)/2p
tan@ ÷ sec@ = [(p²−1)/2p]=[(p²+1)/2p] sin@= (p²-1)/(p²+1)
NEVER
SUCCESS
Shivajik Ambitious
Similar questions