Question

if sec A + tan A = p , prove that sinA = p²-1 / p²+1​

Answer 1

Step-by-step explanation:

we know that sec^2 A - tan^2 A =1

Then using formula

${a}^{2} - b {}^{2} = (a + b)(a - b)$

we get sec A - tan A = 1/p

• 2tan A = p+(1/p)
• tan A = (p^2 + 1)/2p
• after that using Pythagoras theorem we can find out sinA

Answer 2

Answer:

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