Question

if sec A +tan A= P , then find the value of sec A - tan A ?​

Answer 1

Answer:

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Step-by-step explanation:

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Given secA + tan A = p

Recall the identity, sec2A – tan2A = 1

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1

∴ (secA – tanA) = 1/p

Answer 2

Answer:

Given secA + tan A = p

Recall the identity, sec2A – tan2A = 1

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1

∴ (secA – tanA) = 1/p