Question

If (sec A +tan A) (sec B+tan B) (sec C+tan C) = (sec A-tan A) (sec B-tan B) (sec C-tan C), prove
that each of the side is equal to 1.​

Answer 1

Answer:

(sec A +tan A) (sec B+tan B) (sec C+tan C) = (sec A-tan A) (sec B-tan B) (sec C-tan C)=a

(sec A +tan A) (sec B+tan B) (sec C+tan C)=a

multiply by (sec A-tan A) (sec B-tan B) (sec C-tan C) both side

then 1=a (sec A-tan A) (sec B-tan B) (sec C-tan C) first side = 1

similarly another =1

Hence proved