Question

If sec A+tan A=x obtain the value of sec A, tanA and sinA in

Answer 1

Hi ! [ Think that sin A as P]

secA + tanA = p                   - ------>(1) 

We know that, 
sec²A-tan²A = 1

i.e.,

(a+b) (a-b) = a² - b²

⇒ (secA + tanA)(secA-tanA) = 1

⇒  (secA-tanA) = 1/p                   ----->(2)


Adding (1) and (2)
we get ,

2 secA = p + 1/p

2tanA = p - 1/p   

Now, 

2tanA/2secA = sin A

{p - 1/p } / {p + 1/p} = sin A

so,

p² - 1/p² + 1 = sinA

HOPE THAT IT IS HELPFUL.........


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