Question

If sec A + tan A = x, then sec A =​

Answer 1

Step-by-step explanation:

SecA + tanA = x ... ( 1 ) 

=> 1/(secA - tanA) = x as (sec A + tan A)(sec A - tan A) = sec^2 A - tan ^2 A = 1 

=> secA - tanA = 1/x ... ( 2) 

Subtracting Eqn. ( 2 ) from eqn. ( 1 ), 

2tanA = x - 1/x 

=> tanA = (1/2) (x - 1/x).