if sec A + tan A =x, then tan A =
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Step-by-step explanation:
secA + tanA=x... (1) => 1/(secA - tanA) = x as (sec A + tan A) (sec A - tan A) = sec^2 A - tan ^2 A = 1 => secA - tanA= 1/x ... (2) Subtracting Eqn. (2) from eqn. (1), 2tanA = x - 1/x => tanA= (1/2) (x - 1/x).
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