Question

If sec A+tan A=y then tan A =
​

Answer 1

Answer:

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Answer 2

Answer:

$\tan(a) = \frac{ {y}^{2} - 1 }{2y}$

Step-by-step explanation:

sec²A =(y - tanA) ²

= sec²A = y² + tan² A - 2y tan A

= sec² A - tan² A = y² - 2y tan A

= 1 = y² - 2y tan A

$\tan(a) = \frac{ {y}^{2} - 1 }{2y}$

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