Math, asked by kavyasree80lakkakula, 8 months ago

If sec A tan B+ tan A sec B=2, sec A sec B+ tan A tan B =k, k²=

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Answered by shagunjain9
1

Answer:

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MATHS

If secAtanB+tanAsecB=91, then the value of (secAsecB+tanAtanB)

2

is equal to

December 20, 2019

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Vrinda Nimbalkar

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ANSWER

Given secAtanB+tanAsecB=91

Squaring both sides, we get

⇒sec

2

Atan

2

B+tan

2

Asec

2

B+2tanAtanBsecAsecB=8281

⇒2tanAtanBsecAsecB=8281−sec

2

Atan

2

B−tan

2

Asec

2

B ...(1)

Consider, (secAsecB+tanAtanB)

2

=sec

2

Asec

2

B+tan

2

Atan

2

B+2tanAtanBsecAsecB

=sec

2

Asec

2

B+tan

2

Atan

2

B+8281−sec

2

Atan

2

B−tan

2

Asec

2

B (by (1))

=sec

2

A−tan

2

A+8281

=8282

Hope it will help you

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Answered by lakshita200889
3

Answer:

nothing is clear. please mark me as brainest

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