If Sec A-tanA=4 then cosec A
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Sec A-tanA=4 -------- (1)
sec^2A - tan^2A = 1
(Seca-tana)(Seca+tana) = 1
(4)(Seca+tana) = 1
Seca+tana = 1/4 ---------- (2)
On Adding (1) & (2
Seca - tana + Seca + tana = 4 + 1/4
2seca = 17/4
Seca = 17/8 ---------- (3)
On subtracting (1) & (2), we get
Seca+tana - (seca - tana) = 4 - 1/4
Seca + tana - seca + tana = 15/4
2tana = 15/4
tana = 15/8 ---------- (4)
We know that cosec theta = sec theta/tan theta
Therefore, cosec a =17/8/15/8=17/15
Hope its correct<3
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