Question

if sec α and cosec α are the roots of x²-px+q=0​

Answer 1

Answer:

p2 = q (q +2)

Since sec α + cosec α = p and sec α . cosec α = q

[cos α + sin α] / [cos α . sin α] = p and [1] / [cos α . sin α] = q

(cos α + sin α)2 = p2 sin2 α sin2 α

1 + 2 sin α cos α = p2 (1 / q2)

q2 + 2q = p2

Step-by-step explanation:

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