If Sec O = 5/4 than find cost and tan O.
Answers
Answer:
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Explanation:
Sec O= 5/4
Cos O = 4/5. ( Cos0= 1/secO)
1+tan^20 = sec^2O
1+ tan^2O = (5/4)^2
= 25/16-1
=25 - 16/16
= 9/16
= 3/4(taking square root)
TanO = 3/4
Answer:
The answer will be:
cos θ = 4/5;
tan θ = 3/4;
Explanation:
Given;
sec θ = 5/4;
We know that sec θ = 1/cos θ;
Thus, cos θ = 1 / sec θ;
= 1 / (5/4);
= 4/5;
We know that, sec θ = Hypotaneus/ Base of triangle.
From given and the above formula, we can conclude that;
Hypotaneus = 5;
Base of triangle = 4;
Hence, height equal;
√{(5)^2 - (4)^2};
√(25 - 16);
√9;
3 units.
Thus, the height of the triangle = 3 units.
Now, tan θ = Height / Base;
Thus, tan θ = 3/4;
That's all.