Question

If sec Ø+ tan 0+1=Ø then (sec Ø - tan Ø) = ?
(a) 1
(b) -1
(c) O
(d) 2




TELL ME THE AÑŠWÊŘ!BŘØ!!!!​

Answer 1

Answer:

b. -1

Step-by-step explanation:

$sec^{2}$Ф-$tan^{2}$Ф=1

according to the identity, (a+b)(a-b)=$a^{2}- b^{2}$

(secФ+tanФ)(secФ-tanФ)=1

we have, secФ+tanФ=-1

1(secФ-tanФ)=-1

secФ-tanФ=-1

Answer 2

Answer:

-1 is your answer friend