if sec ø+ tanø=2 then find the value of sec⁵ø+tan⁵ø
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Step-by-step explanation:
Answer
secθ+tanθ=2⟶(1)
Now, sec
2
θ−tan
2
θ=1
⇒(secθ−tanθ)(secθ+tanθ)=1
⇒2(secθ−tanθ)=1
⇒secθ−tanθ=
2
1
⟶(2)
Adding equations (1)&(2), we get
⇒2secθ=2+
2
1
=
2
5
⇒secθ=
4
5
Or cosθ=
5
4
Now, sinθ=
1−cos
2
θ
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