If sec ø+tanø= P then show that p²-1/p²+1=sin ø
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Answer:
I hope ,this will help you
Step-by-step explanation:
Given that,
Secθ+tanθ=p..................(1)
⇒(Secθ+tanθ)(Secθ−tanθ)=1
⇒p(Secθ−tanθ)=1
⇒(Secθ−tanθ)=
p
1
.........(2)
Addequations(1)and(2)weget
⇒Secθ+tanθ+Secθ−tanθ=p+
p
1
⇒2secθ=
p
p
2
+1
⇒secθ=
2p
p
2
+1
∴cosθ=
p
2
+1
2p
sinθ=
1−cos
2
θ
=
1−(
p
2
+1
2p
)
2
=
(p
2
+1)
2
(p
2
+1)
2
−4p
2
=
(p
2
+1)
2
p
4
+2p
2
+1−4p
2
=
(p
2
+1)
2
p
4
−2p
2
+1
=
(p
2
+1)
2
(p
2
−1)
2
Hence,sinθ=
p
2
+1
p
2
−1
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