Question

if sec Q = 13/5 show that 2sin Q - 3 cos Q / 4 sin Q - 9 cos Q​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

HEY MATE!!HERE IS YOUR ANSWER

secθ= 13/5

secθ= H/B=13/5

Using Pythagoras theorem:-

H^2=P^2+B^2

13^2=P^2+5^2

P^2=144

P=12

Now, 2Sinθ-3Cosθ/4Sinθ-9Cosθ

=2(12/13)-3(5/13)/4(12/13)-9(5/13)

=24-15/13/48-45/13

=3 Ans!!

Hope it helps!!