Question

if sec Q =2 then value of cosec Q is​

Answer 1

Answer:

Let cscθ−cotθ=q        ...(1)

cscθ+cotθ(cscθ−cotθ)(cscθ+cotθ)=q⇒cscθ+cotθcsc2θ−cot2θ=q

⇒cscθ+cotθ=q1          ...(2)

Adding (1) & (2) we get,

2cscθ=q+q1∴cscθ=21(q+q1)

Ans: C

Answer 2

Answer:

2/√3

Step-by-step explanation:

SecQ= 2

CosQ=1/2 ,{ secQ=1/SecQ}

Since,Sin^2Q+ Cos^2Q=1

we get sinQ= √3/2

So, CosecQ= 2/√3 ,{ sinQ= 1/CosecQ}