If sec Q = x+1/4x find secQ+tanQ = 2x or 1/2x?
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Answer:
secA=x+1/4x
sec?A=(x+1/4x)2 =x?+2.x.1/4x+1/16x?
=x?+1/2+1/16x?
Now, sec?A-tan?A=1 or, tan?A=sec’A-1
or, tan?A=x2+1/2+1/16x2-1 or, tan?A=x2+1/16x2-1/2
or, tanA=x2-2.x.1/4x+1/16x2
or, tan?A=(x-1/4x)
or, tanA=+-(x-1/4x)
*, either, secA+tanA
=x+1/4x+x-1/4x [when tanA=x+1/4x]
=2x
or, secA+tanA
=x+1/4x-x+1/4x [when tanA=-(x+1/4x)]
=1/4x+1/4x
=2/4x
ʜᴇʟᴘғᴜʟ ғᴏʀ ʏᴏᴜ✨
=1/2x (Proved)
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