if sec square A ( -1sinA )(1+sinA ) = k find the value of k
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If, sec²A (1-sinA) (1+sinA) = k, find the Value of k
=> k = 1
Step-by-step explanation:
sec²A (1-sinA) (1+sinA) = k
sec²A [ (1)² - (sinA) ² ] = k
sec²A (1-sin²A) = k
sec²A cos²A = k
sec²A (1/sec²A) = k
1= k
k = 1
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