Question

If sec θ – tan θ = 1/3, then find the value of (sec θ + tan θ).​

Answer 1

Answer:

3

Step-by-step explanation:

sec square theta - tan square theta = 1

, (sec theta + tan theta )( sec theta - tan theta) = 1

, ( sec theta+tan theta) × 1/3 = 1

, ( sec theta+ tan theta)= 3

Answer 2

Step-by-step explanation:

given ,sec ∅-tan∅ =1

using , sec²∅= tan²∅+1

sec²∅-tan²∅=1

$(\sec(x) + \tan(x) )( \sec(x) - \tan(x) ) = 1 \\ ( \sec(x) + \tan(x) ) = \frac{1}{( \sec(x) - \tan(x) )} \\ \: \: \: \: \: \: \: = \frac{1}{1 \div 3} \\ \: \: \: \: \: \: \: = 3$