Question

If sec⁡θ-tan⁡θ=1/5, then the value of sec⁡θ+tan⁡θ is

Answer 1

Answer:

We know that

${sec}^{2} θ \: - {tan}^{2} θ \: = 1$

$\implies\: (sec⁡θ-tan⁡θ) (sec⁡θ+tan⁡θ) = 1$

$\implies \ (\frac{1}{5}) \times (sec⁡θ+tan⁡θ) = 1$

$\implies \: (sec⁡θ+tan⁡θ) = 5$

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