if secθ + tanθ=2/3 then secθ-tanθ=
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Since we know that , sec²θ - tan²θ = 1
⇒ (secθ + tanθ)(secθ - tanθ) = 1
⇒ (2/3)(secθ - tanθ) = 1
⇒ secθ - tanθ = 3/2
⇒ (secθ + tanθ)(secθ - tanθ) = 1
⇒ (2/3)(secθ - tanθ) = 1
⇒ secθ - tanθ = 3/2
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