Math, asked by bharathkaripe0279, 6 months ago

If secθ+tanθ= 3 , then secθ-tanθ =​

Answers

Answered by pankajsrivastavak197
1

We know that

sec²x= 1+tan²x

sec²x-tan²x= 1

(sec x + tan x) (sec x - tan x) = 1

(3) ( sec x - tan x) = 1

(sec x - tan x) = ⅓

Answered by lavanyakatta
0

Step-by-step explanation:

Sorry I am not able to tell you this answer

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